posted by Mark on .
A diver running 1.8m/s dives out horizontally from the edge of a vertical cliff and 3.0s later reaches the water below. How high was the cliff, and how far from its base did the diver hit the water?
h = ½gt², since diver's initial vertical speed is 0
h = 44 m
x = vt
x = 5.4 m