Please help
the question that I got is:
Calculate how much 95% ethyl alcohol will be required to dissolve 075g sulfanilamide at 78 degree Celsius. Knowing that solubility of sulfanilamide is 210 mg/ml at 78 degree Celsius, 14mg/ml at 0 Degree Celsius.
please explain.
You only need to consider the solubility at 78C.
So if you need to dissolve 75 g then you need
75g/0.210 g ml^-1 = 357 ml or 360 ml to 2 sig figs.
thank you!
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To calculate how much 95% ethyl alcohol is required to dissolve 0.075g of sulfanilamide at 78 degrees Celsius, we need to consider the solubility of sulfanilamide at that temperature.
Given that the solubility of sulfanilamide is 210 mg/ml at 78 degrees Celsius, we can convert the mass of sulfanilamide (0.075g) to milligrams:
0.075g * 1000 = 75 mg
Now, we can calculate the volume of 95% ethyl alcohol needed to dissolve 75 mg of sulfanilamide. We'll use the formula:
Volume of solution = Mass of solute / Solubility
Volume of solution = 75 mg / 210 mg/ml
Volume of solution = 0.357 ml
Since we are dealing with 95% ethyl alcohol, we need to take into account the concentration. 95% ethyl alcohol means that 95 ml of the solution is pure ethyl alcohol, while the remaining 5 ml is water.
To find out the volume of 95% ethyl alcohol needed, we need to divide the volume of the solution by the concentration of ethyl alcohol:
Volume of 95% ethyl alcohol = Volume of solution / (Concentration of ethyl alcohol / 100)
Volume of 95% ethyl alcohol = 0.357 ml / (95 / 100)
Volume of 95% ethyl alcohol = 0.375 ml
Therefore, you would need approximately 0.375 ml of 95% ethyl alcohol to dissolve 0.075g of sulfanilamide at 78 degrees Celsius.
Than from here I need to find:
Using the volume of solvent calculated in step 1, calculate how much sulfanilamide will remain dissolved in the mother liquor after the mixture is cooled to 0 degree Celsius?
Can you please explain?