How many calories are required at 0 degrees Celsius to melt an ice cube with a mass of 25 g? Explain in detail. I don't understand.
calories = mass ice x heat fusion.
To calculate the amount of calories required to melt an ice cube, we can use the formula:
Q = m * ΔHf
Where:
Q = amount of heat energy (in calories)
m = mass of the ice cube (in grams)
ΔHf = heat of fusion (specific latent heat for melting ice) (in calories per gram)
First, let's find the value of ΔHf. The heat of fusion for ice is approximately 79.7 calories per gram.
Next, substitute the values into the formula:
Q = 25 g * 79.7 cal/g
Q = 1992.5 calories
Therefore, it would require approximately 1992.5 calories to melt an ice cube with a mass of 25 grams at 0 degrees Celsius.
To calculate the number of calories required to melt an ice cube, we need to understand the concept of heat transfer and specific heat capacity.
At 0 degrees Celsius (also known as the melting point of ice), the ice cube absorbs heat from its surroundings to increase its temperature and eventually melt. The process of melting ice requires energy, which is transferred in the form of heat.
To determine the number of calories required, we can use the formula:
Q = m * c * ΔT
where:
Q is the heat energy transferred (in calories),
m is the mass of the ice cube (in grams),
c is the specific heat capacity of ice (in calories/gram-degree Celsius), and
ΔT is the change in temperature (in degrees Celsius).
Since we want to melt the ice at 0 degrees Celsius, ΔT is 0. However, we still need to calculate the initial temperature difference between the ice and its surroundings.
Assuming the initial temperature of the ice cube is -10 degrees Celsius, the temperature difference (ΔT) would be:
ΔT = 0°C - (-10°C) = 10°C
Now, we need to find the specific heat capacity of ice. The specific heat capacity is the amount of heat energy required to raise the temperature of a substance by 1 degree Celsius per gram. For ice, it is approximately 0.5 calories/gram-degree Celsius.
Now we can substitute the values into the formula:
Q = 25g * 0.5 cal/g°C * 10°C
Q = 125 calories
Therefore, to melt an ice cube with a mass of 25 grams at 0 degrees Celsius, approximately 125 calories of heat energy are required.