Posted by Jordan on Monday, September 20, 2010 at 11:03pm.
This is the same as probability of 2, 3, 4 or 5 dinners being selected.
P(2) = 5/13 * 4/12 * 8/11 * 7/10 * 6/9 = ?
P(5) = 5/13 * 4/12 * 3/11 * 2/10 * 1/9 = ?
Probability of P(2), P(3), P(4) or P(5) = sum of these probabilities.
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