An unknown substance has a mass of 17.3 . When the substance absorbs 1.557×102 of heat, the temperature of the substance is raised from 25.0 to 45.0 . What is the most likely identity of the substance?
q = m x Cg x (Tf - Ti)
http://www.ausetute.com.au/heatcapa.html
find Cg.
17.3 WHAT?
25 WHAT? 45 WHAT?
To determine the identity of the substance, we can use the equation q = mcΔT, where q represents the amount of heat absorbed, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
First, let's calculate the change in temperature:
ΔT = final temperature - initial temperature
ΔT = 45.0 °C - 25.0 °C
ΔT = 20.0 °C
Next, let's rearrange the formula to solve for specific heat capacity (c):
c = q / (m * ΔT)
Now we can substitute the given values into the equation:
c = (1.557×102 J) / (17.3 g * 20.0 °C)
c = 1557 J / 346 g°C
To simplify the unit, we divide both the numerator and denominator by 346:
c ≈ 4.50 J/g°C
By comparing this specific heat capacity value to known substances, we can determine the most likely identity of the substance.