Posted by Anonymous on Monday, September 20, 2010 at 10:46pm.
the ball starts with a speed of 0 and accelerates to 44 m/s in a distance of 3.5m
use:
vf^2=v0^2+2ad
vf=final speed = 44m/s
v0=initial speed = 0
a=accel (to be determined)
d= distance = 3.5 m
44^2=0+2ax3.5
a=44^2/7 = 276.6 m/s/s
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