Posted by Anonymous on Monday, September 20, 2010 at 9:21pm.
My question says:
Find the exact alue of x for which (4^x)*(5^[4x+3])=(10^[2x+3])
I can't seem to come to a solution.
We're reviewing last year's lessons, so change of base and logarithmic expressions are what we're going over right now.
Here's what I've done so far:
(4^x)*(5^[4x+3])=(10^[2x+3])
log both sides
log[(4^x)*(5^[4x+3])]=log[(10^[2x+3])]
(xlog4)+([4x+3]log5)=([2x+3]log10)
since log10=1
(xlog4)+([4x+3]log5)=(2x+3)
Have I started correctly? Where do I go from here? Please be detailed, I want to understand this.

Math  MathMate, Monday, September 20, 2010 at 9:36pm
Proceed and solve for x in terms of ln.
I get x=ln(8)/ln(25).

Math  Anonymous, Monday, September 20, 2010 at 9:41pm
How do I proceed? I really have no clue where to go from where I've stopped! Usually I can simply factor out an x from the LS, but here I can't do that. Could you please show me your solution with every step? It would be so helpful.
Thank you in advance :)

Math  MathMate, Monday, September 20, 2010 at 9:51pm
It is a linear equation with numerical coefficients (log4, etc.).
Expand
(xlog4)+([4x+3]log5)=(2x+3)
to give
xlog4 + 4xlog5  2x = 3 3log5
Factor out x on the LHS and solve for x.
All the log4, log5 are numerical values that you can simplify eventually.

Math  Anonymous, Monday, September 20, 2010 at 10:02pm
Sorry to keep bugging, but I followed what you told me and got to:
x=(3[log125])/([log2500]2)
How can I get to the answer from that? I don't know how to deal with the 3 and the 2 that are still lying around.

Math  Anonymous, Monday, September 20, 2010 at 10:09pm
Alright, what I did now was:
since log10=1, log100=2, and log1000=3
So I plugged that in to what I had
x=(log1000log125)/(log2500log100)
x=(log[1000/125])/(log[2500/100])
x=(log8)/(log25)
Is that what I was supposed to do?
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