A frog with a mass of .14kg jumps by extending its legs 13.5cm, starting from rest in a time period of 112ms. What is the acceleration of the frog while it jumps?

To find the acceleration of the frog while it jumps, we can use the formula:

acceleration = (change in velocity) / (time taken)

In this case, we need to find the change in velocity. Since the frog starts from rest, its initial velocity is 0 m/s. To find the final velocity, we can use the formula for average velocity:

average velocity = (initial velocity + final velocity) / 2

Given that the frog extends its legs 13.5 cm, we can convert this distance to meters by dividing by 100: 13.5 cm / 100 = 0.135 m.

Since the frog starts from rest, its initial velocity is 0 m/s. The final velocity can be found using the formula:

final velocity = (2 * average velocity) - initial velocity

Substituting in the known values:

final velocity = (2 * 0.135 m/s) - 0 m/s = 0.27 m/s

Now we can calculate the acceleration:

acceleration = (change in velocity) / (time taken)

Given that the time taken for the jump is 112 ms, we need to convert this to seconds: 112 ms / 1000 = 0.112 s

Substituting in the known values:

acceleration = (0.27 m/s - 0 m/s) / 0.112 s = 2.41 m/s^2

Therefore, the acceleration of the frog while it jumps is 2.41 m/s^2.