what will be the final temperature if a 5.00-g block of aluminum at 37.0 celsius gives off 25.0 J of heat to its surroundings?
q = m x Cg x (Tf - Ti)
http://www.ausetute.com.au/heatcapa.html
q=-25.0J
To determine the final temperature of the aluminum block, we can use the equation:
q = mcΔT
Where:
q is the heat transferred
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature
We rearrange the equation to solve for ΔT:
ΔT = q / (mc)
Now, we can substitute the given values into the equation:
q = 25.0 J
m = 5.00 g
c = specific heat capacity of aluminum (which is 0.90 J/g°C)
ΔT = 25.0 J / (5.00 g * 0.90 J/g°C)
Calculating the value:
ΔT = 5.56°C
Since the aluminum block initially starts at 37.0°C, we can find the final temperature by subtracting ΔT from the initial temperature:
Final temperature = 37.0°C - 5.56°C
Final temperature = 31.44°C
Therefore, the final temperature of the aluminum block will be approximately 31.44°C.