Find the real solutions of each equation.

1) 1 / (x+6)^2 = 1 / (x+6) + 12

2) 8x^2/3 - 39x^1/3 - 5 = 0

I have no idea how to do these. Please help!!! Thank you!

1.

Multiply both sides by (x+6)^2 to get
1-(x+6)-12(x+6)²=0
Expand and solve for x.

2. Substitute y=x^(1/3) and solve for the resulting quadratic in y.