When the shuttle bus comes to a sudden stop

to avoid hitting a dog, it decelerates uniformly
at 3.8 m/s2 as it slows from 8.8 m/s to 0 m/s.
Find the time interval of acceleration for
the bus.
Answer in units of s.

To find the time interval of acceleration for the bus, we can use the formula for acceleration:

acceleration (a) = (final velocity - initial velocity) / time

Given:
Initial velocity (u) = 8.8 m/s
Final velocity (v) = 0 m/s
Acceleration (a) = -3.8 m/s^2 (negative sign indicates deceleration)

We need to find the time (t) taken for the bus to decelerate from 8.8 m/s to 0 m/s.

Rearranging the formula, we have:

t = (v - u) / a

Substituting the values into the formula:

t = (0 - 8.8) / -3.8

Now we can calculate the time interval:

t = (-8.8) / (-3.8)

Dividing -8.8 by -3.8, we get:

t ≈ 2.32 seconds

Therefore, the time interval of acceleration for the bus is approximately 2.32 seconds.