Monday

October 20, 2014

October 20, 2014

Posted by **Chelsea** on Monday, September 20, 2010 at 11:35am.

f(x)= square root of x, g(x)= cube root of 1-x

These are my answers, but I am not sure about them and I only figured out one domain... that is the part that really confuses me. Help please!

a) 5th root of 1-x

Domain?

b) The cube root of (1 minus the square root of x)

Domain?

c) Fourth root of x

Domain= [0, infinity]

d) The cube root of (1 minus the cube root of 1 minus x)

Domain?

- Calc -
**bobpursley**, Monday, September 20, 2010 at 11:45ama. Odd roots of negative numbers can be negative, thus (-32)^1/5 has a root -2. So the domain of x is all real x.

b.same argument

c. you cannot take the even root of a negative number, so you are correct.

d. same a,b

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