Solid magnesium metal reacts with chlorine gas according to the following equation:

Mg + Cl2 --> MgCl2

What mass of magnesium chloride is formed in the reaction between 7 g of Mg and 13.2 g of Cl2

I got 7/24.3= .288
13.2/70.90= 1.861777

thats as far as i got and im stuck and don't know what to do next

YOu got moles of Mg, and moles of Cl2. The reaction then will be limited by the moles of Mg.

So you will get .288moles of MgCl2

massMgCl2=.288*molmassMgCl2

The equation is limited by the element you have the least moles of.

In this case it will be the Cl2. 13.2/70.9 = .1862 mol

massMgCl2 = .1862 mol * molmassMgCl2

To determine the mass of magnesium chloride formed in the reaction, you need to use the concept of stoichiometry.

Step 1: Write down the balanced equation for the reaction:
Mg + Cl2 --> MgCl2

Step 2: Calculate the number of moles of each reactant.
To do this, divide the given mass of each element by its molar mass.
For magnesium (Mg):
Number of moles = Given mass / Molar mass
Number of moles = 7 g / 24.3 g/mol = 0.288 mol (you have already calculated this correctly)

For chlorine (Cl2):
Number of moles = Given mass / Molar mass
Number of moles = 13.2 g / (2 * 35.45 g/mol) = 0.186 mol (you have already calculated this correctly)

Step 3: Determine the limiting reactant.
The limiting reactant is the one that is completely consumed in the reaction, limiting the amount of product that can be formed.
To find the limiting reactant, compare the number of moles of magnesium (0.288 mol) and chlorine (0.186 mol). The reactant with fewer moles is the limiting reactant. In this case, chlorine is the limiting reactant.

Step 4: Use the stoichiometry of the balanced equation to find the number of moles of magnesium chloride formed.
From the balanced equation, the stoichiometric ratio between magnesium and magnesium chloride is 1:1.
Therefore, the number of moles of magnesium chloride formed is also 0.186 mol.

Step 5: Calculate the mass of magnesium chloride formed.
To do this, multiply the number of moles of magnesium chloride by its molar mass.
Mass of MgCl2 = Number of moles * Molar mass
Mass of MgCl2 = 0.186 mol * 95.2 g/mol = 17.68 g (rounded to two decimal places)

So, the mass of magnesium chloride formed in the reaction between 7 g of Mg and 13.2 g of Cl2 is approximately 17.68 g.