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March 30, 2017

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A car initially traveling northeast (45° N of E) at 28.3 m/s takes 6.0 s to turn to the east. After the turn, the car is traveling due east at 20.0 m/s. What is the value and direction of the change in velocity?

  • College Physics - ,

    change in velocity= finalvelocity-initialvelocity

    breakthe initial velocity into N,E components.

    Vi=28.3*.707N+28.3*.707E
    Vf=20 E

    subtract. change in velocity=Vf-Vi

  • College Physics - ,

    thank you

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