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February 1, 2015

February 1, 2015

Posted by **Bob** on Sunday, September 19, 2010 at 8:21pm.

Does this absolutely converge, conditionally converge, or diverge?

- calculus -
**MathMate**, Sunday, September 19, 2010 at 11:26pmGroup every 6 terms (1 cycle) together and consider as an aggregate term for a new series, ΣQn. Assume that all the terms are positive because of the n! in the denominator.

If you can prove that

Qn+1/Qn < 1, then

by the ratio test, the (new) series is absolutely convergent.

Can you take it from here?

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