Saturday

April 18, 2015

April 18, 2015

Posted by **Chip** on Sunday, September 19, 2010 at 4:02pm.

- physics -
**bobpursley**, Sunday, September 19, 2010 at 4:18pmdistance train=1/2 a t^2

distance passenger=V*(t-6)

set them equal

1/2 a t^2=Vt-6V

.22t^2-Vt+6V=0

t=(V+-sqrt(V^2-.88*6V)/.44

Well, V^2>.88*6V

V>5.20m/s

Lets see if it works.

t=(5.20+-sqrt(0))/.44=12 seconds

distance train: 1/2 .44*144=you do it

distance passenger= 5.20(12-6)=you do it

- physics -
**yoyo**, Sunday, August 31, 2014 at 10:06pmno

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