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April 1, 2015

April 1, 2015

Posted by **Melissa** on Sunday, September 19, 2010 at 2:49pm.

- physics -
**Damon**, Sunday, September 19, 2010 at 3:07pmit falls

initial speed up = Vi = 8 sin 40

y = yo + Vi t -4.9 t^2

0 = 1 + 8 sin 40 t -4.9 t^2

solve for t, time to hit ground

horizontal velocity u = 8 cos 40 forever

find v at t = time to hit ground

v = Vi -9.8 t (will be negative, down)

tan angle = v/u

magnitude speed = sqrt(u^2+v^2)

- physics -
**Melissa**, Sunday, September 19, 2010 at 3:33pmWhen it says magnitude of velocity is that the same as the final velocity before impact? The word "magnitude" threw me off.

- physics -
**Damon**, Sunday, September 19, 2010 at 5:21pmmagnitude is the size sqrt (u^2+v^2)

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