physics
posted by Anonymous on .
While exploring a cave, a spelunker starts at the entrance and moves the following distances: 75.0 m north, 290 m east, 180 m at an angle 30.0° north of east, and 150 m south. Find the resultant displacement from the cave entrance.

break it down to horizontal (x) and vertical (y) components!
horizontal
x = 290m + 180(cos30)m
vertical
y = 75m + 180(sin30)m 180 m
perform Pythagorean theorem
sqrt(x^2 + y^2)=?
displacement also has direction:
tan^1(y/x)=?