What is the conjugate base of the following substances:
a. (CH3)3NH /(CH3)3N
b. H3N-CH2-COOH / H3N-CH2-COO
c. H3N-CH2-COO / H2N-CH2-COO
d. OOC-CH2-COOH / OOC-CH2-COO
e. OOC-CH2-COOH / HOOC-CH2-COOH
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To determine the conjugate base of a substance, you need to identify the substance's acid and remove a proton (H+) to form the conjugate base.
a. (CH3)3NH / (CH3)3N:
The acid is (CH3)3NH, which can donate a proton. Its conjugate base is formed by removing a proton, resulting in (CH3)3N.
b. H3N-CH2-COOH / H3N-CH2-COO:
The acid is H3N-CH2-COOH (glycine). It can donate a proton. Removing a proton from the acid form gives you the conjugate base H3N-CH2-COO.
c. H3N-CH2-COO / H2N-CH2-COO:
The acid is H3N-CH2-COOH (glycine). It can donate a proton. Removing a proton from this acid form gives you the conjugate base H2N-CH2-COO.
d. OOC-CH2-COOH / OOC-CH2-COO:
The acid is OOC-CH2-COOH (oxalic acid). Upon donation of a proton, the conjugate base formed is OOC-CH2-COO.
e. OOC-CH2-COOH / HOOC-CH2-COOH:
The acid is OOC-CH2-COOH (oxalic acid). Taking away a proton gives you the conjugate base HOOC-CH2-COOH.
Remember, the conjugate base is formed when an acid donates a proton (H+), resulting in the removal of the acidic hydrogen.