Posted by J on Saturday, September 18, 2010 at 7:11pm.
well, exactly opposite.That means the time the bullet went across the car, the train advanced the same distance as the angle of the bullet would have advanced.
Assume Theta is the angle the bullet entered.
Hmmmm. to figure the time the bullet took to cross the car, one needs to know the width of the car.
distance the car advanced:
distance=bulletspeed*time*sinTheta
Now the train: it advanced
distance=trainspeed*time
set them equal.
bulletspeed*sinTheta=transpeed*time
theta=arc sin (trainspeed/bulletspeed)
bullet speed is .8 of 650 Be certain to change km/hr to m/s
What?
I'd love to know where this train came from...
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