Posted by **Jessica** on Saturday, September 18, 2010 at 4:38pm.

How many ml of 50% dextrose should be added to 1 L of 0.9% NaCl to make a 5% dextrose solution?

- medicine -
**bobpursley**, Saturday, September 18, 2010 at 5:04pm
I am wondering if your percents are by mass, or what?

- medicine -
**Jessica**, Saturday, September 18, 2010 at 5:07pm
I don't know it never said in the problem.

- medicine -
**MathMate**, Saturday, September 18, 2010 at 5:50pm
It is understood to be mass/volume for ease of dosage calculations.

Therefore whether it is 0.9% saline or simply water, the proportions are the same.

You can do the calculations as follows:

Suppose we need v ml of c1% concentrated dextrose diluted with 1000 ml of liquid to give a c2% solution,

mass of glucose added = v(c1/100) g

total volume of liquid = 1000+a

Therefore

(c2/100) = (v c1/100)/(1000+v)

Solving for v

(1000+v)c2 = v c1

v=1000c2/(c1-c2) ....(1)

For the case in point,

x=50, y=5

v=1000*5/(50-5)

= 111.1 ml.

Equation 1 is a handy formula to remember if you need to do the same calculation often and fast.

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**TutorCat**, Saturday, September 18, 2010 at 5:53pm
I don't think adding salt would matter. The only one thing you're focusing on is how to make that 5% dextrose solution.

(x mL)*(50) + 1000 mL = (1000 mL + x) mL)*(5)

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