How many ml of 50% dextrose should be added to 1 L of 0.9% NaCl to make a 5% dextrose solution?

I am wondering if your percents are by mass, or what?

I don't know it never said in the problem.

It is understood to be mass/volume for ease of dosage calculations.

Therefore whether it is 0.9% saline or simply water, the proportions are the same.

You can do the calculations as follows:

Suppose we need v ml of c1% concentrated dextrose diluted with 1000 ml of liquid to give a c2% solution,

mass of glucose added = v(c1/100) g
total volume of liquid = 1000+a
Therefore
(c2/100) = (v c1/100)/(1000+v)
Solving for v
(1000+v)c2 = v c1
v=1000c2/(c1-c2) ....(1)

For the case in point,
x=50, y=5
v=1000*5/(50-5)
= 111.1 ml.

Equation 1 is a handy formula to remember if you need to do the same calculation often and fast.

I don't think adding salt would matter. The only one thing you're focusing on is how to make that 5% dextrose solution.

(x mL)*(50) + 1000 mL = (1000 mL + x) mL)*(5)

To find out how many milliliters (ml) of 50% dextrose should be added to 1 liter (L) of 0.9% NaCl to make a 5% dextrose solution, we need to use the concept of dilution.

First, let's determine the amount of dextrose solution needed. We are starting with 1 L of the NaCl solution, and we want the final concentration to be 5%. This means that we need a total of 5% of 1 L to be dextrose. In other words, we need 0.05 L (or 50 ml) of dextrose solution.

Next, we need to determine the concentration of the 50% dextrose solution. This means that 50 ml of the 50% dextrose solution contains 50% of dextrose. To calculate the volume of the 50% dextrose solution needed to have 50 ml of dextrose, we can use the following equation:

(50 ml dextrose) / (0.5 dextrose fraction) = X ml 50% dextrose

Simplifying this equation, we get:

50 ml / 0.5 = X ml

X ml = 100 ml

Therefore, you would need to add 100 ml of the 50% dextrose solution to 1 L of 0.9% NaCl to make a 5% dextrose solution.