Posted by John on .
Consider a 1.50-g mixture of magnesium nitrate and magnesium chloride. After dissolving this mixture in water, 0.500M of silver nitrate is added dropwise until precipitate formation is complete. The mass of the white precipitate formed is 0.641 g. Calculate the mass percent of magnesium chloride in the mixture?
0.641 g AgCl x (1 mole MgCl2/2 moles AgCl) = 0.641 x (95.21/2*143.32) =?? g MgCl2.
% MgCl2 = (g MgCl2/1.5 g sample)*100 = ??
% Mg(NO3)2 = 100 - %MgCl2.