Homework Help: Chemistry

Posted by John on Saturday, September 18, 2010 at 10:39am.

Consider a 1.50-g mixture of magnesium nitrate and magnesium chloride. After dissolving this mixture in water, 0.500M of silver nitrate is added dropwise until precipitate formation is complete. The mass of the white precipitate formed is 0.641 g. Calculate the mass percent of magnesium chloride in the mixture?

Chemistry - DrBob222, Saturday, September 18, 2010 at 12:39pm
0.641 g AgCl x (1 mole MgCl2/2 moles AgCl) = 0.641 x (95.21/2*143.32) =?? g MgCl2.
% MgCl2 = (g MgCl2/1.5 g sample)*100 = ??
% Mg(NO3)2 = 100 - %MgCl2.

Answer this Question

Related Questions

science - Consider a 1.50-g mixture of magnesium nitrate and magnesium chloride....
chem - a 6.54 g sample consisting of a mixture of silver nitrate and sodium ...
Chemistry - A mixture contains only CuCl2 and FeCl3. A 0.7391 g sample of the ...
chemistry - a mixture containing only sodium chloride and potassium chloride has...
Chem 2 - If we burn a strip of magnesium in air, there will be two main products...
Chemistry - A 4.5 g piece of magnesium ribbon undergoes combustion in air to ...
College Chemistry - A mixture of the compounds sodium oxide and magnesium ...
chemistry - 7. Write the balanced equation for the equation for the reaction of ...
Chemistry - A solution of magnesium chloride, MgCl2, is prepared by dissolving ...
chemistry hw question - Magnesium hydroxide + hydrogen chloride-----> ...

For Further Reading

First Name:
School Subject:
Answer: