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January 25, 2015

January 25, 2015

Posted by **.** on Saturday, September 18, 2010 at 10:25am.

1) Find the maximum height (in m) about the ground that the projectile reaches.

2) Find its distance (in m) from the place where the shell was fired to its landing place when it eventually falls back to the ground.

Solution/explanation, please? Thanks!

- Physics -
**bobpursley**, Saturday, September 18, 2010 at 10:36amfirst, figure the height of the shell.

vertical velocity at launching is 140sin56.

At the top, the vertical velocity of the shell is zero.

Vf^2=Vi^2-2*g*height solve for height.

Now, the second problem, the second projectile. Do it the same way, except vi now is 110sin35

add the two heights.

Now for distance. I will leave that to you, find the distance to the first max height (vcostheta*time), and then the second distance. add them. Careful on your calculations.

- Physics -
**Anonymous**, Thursday, October 25, 2012 at 11:15pmjgm

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