Homework Help: Physics

Posted by . on Saturday, September 18, 2010 at 10:25am.

A shell is launched at 140 m/s 56.0 degrees above the horizontal. When it has reached its highest point, it launches a projectile at a velocity of 110 m/s 35.0 degrees above the horizontal relative to the shell.

1) Find the maximum height (in m) about the ground that the projectile reaches.

2) Find its distance (in m) from the place where the shell was fired to its landing place when it eventually falls back to the ground.

Solution/explanation, please? Thanks!

Physics - bobpursley, Saturday, September 18, 2010 at 10:36am
first, figure the height of the shell.
vertical velocity at launching is 140sin56.

At the top, the vertical velocity of the shell is zero.
Vf^2=Vi^2-2*g*height solve for height.

Now, the second problem, the second projectile. Do it the same way, except vi now is 110sin35

add the two heights.

Now for distance. I will leave that to you, find the distance to the first max height (vcostheta*time), and then the second distance. add them. Careful on your calculations.
Physics - Anonymous, Thursday, October 25, 2012 at 11:15pm
jgm

Answer this Question

Related Questions

Physics - I solved 1 out of 2 correctly: A shell is launched at 140 m/s 56.0 ...
Physics - A 12.0 kg shell is launched at an angle of 55 degrees above the ...
Physics - A projectile is launched with an initial velocity of 268 m/s, at an ...
Physics - A baseball is thrown with an initial velocity of 37 m/s at an angle of...
Physics - A projectile is launched with an initial speed of 40m/s at an angle of...
physics - A rocket is launched at an angle of 56.0° above the horizontal ...
physics - A rocket is launched at an angle of 56.0° above the horizontal ...
Physics - A mortar shell is launched with a velocity of 100m/s at an angle of 30...
physics - An artillery shell is launched on a flat, horizontal field at an angle...
physics - An artillery shell is launched on a flat, horizontal field at an angle...

For Further Reading

First Name:
School Subject:
Answer: