how would one do this problem..
2y^-3 = 4e^(-x/2)/(1+e(-x/2))
I would not call it chemistry.
Are you trying to solve for y in terms of x?
If so, y^3 = (1/2)[e^(x/2) + 1]
Take the cube root of that for y.
2y^-3 = 4e^(-x/2)/(1+e(-x/2))
Are you trying to solve for y in terms of x?
If so, y^3 = (1/2)[e^(x/2) + 1]
Take the cube root of that for y.