posted by MozAngeles on .
When the dried-up seed pod of a scotch broom plant bursts open, it shoots out a seed with an initial velocity of 2.64 m/s at an angle of 30.0˚ below the horizontal. The seed pod is 0.465 m above the ground.
How long does it take for the seed to land?
What horizontal distance does it cover during its flight?
For the time, solve the equation
y = 0.465 + 2.64 sin30 -(g/2) t^2 = 0
= 0.465 + 1.32 -4.9 t^2
There will be two solutions. Take the positive one.
For the horizonal distance traveled, that would be
X = 2.64 cos30*t = 2.29 t
Use the t from the first part.
shouldn't 2.64 (sin30) by multiplied by time?
y = 0.465 + 2.64 (sin30)t -(g/2) t^2 = 0
Yes, thanks for catching that. :-)
0 = 0.465 + 1.32 t -4.9 t^2
also needed a "t" in it.
Where did you get -4.6 from?
I mean -4.9