Posted by **Katie** on Friday, September 17, 2010 at 7:02pm.

A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 3.3 later. If the speed of sound is 340 , how high is the cliff?

- physics -
**drwls**, Friday, September 17, 2010 at 7:18pm
You need to show the units of your numbers. I will assume they are meters and seconds.

Solve this equation for height, H:

3.23 s = time for sound to arrive + time to fall

3.3 = H/340 + sqrt(2H/9.8)

- physics -
**awks**, Thursday, November 15, 2012 at 7:23pm
1.3 (using the given equation...)

- physics -
**ressy**, Saturday, February 14, 2015 at 9:49am
Given:

t=5sec.

Vo=0m/s

g=9.81m/s^2

V=320m/s^2

Solution:

H=Vot+0.5gt^2

H=(0.5)(9.81)(5^2)

H=122.625m

H=vt

H=320(5)

H=1600m

H=122.625+1600

[H=1722.625m] :)

- physics -
**ressy**, Saturday, February 14, 2015 at 10:06am
Given:

t=3.3sec.

Vo=0m/s

g=9.81m/s^2

V=340m/s^2

Solution:

H=Vot+0.5gt^2

H=(0.5)(9.81)(3.3^2)

H=53.42m

H=vt

H=340(5)

H=1700m

H=53.42+1700

[H=1753.42m] :)

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