The speed of the tip of the minute hand on a

town clock is 0.00136 m/s.

(a)What is the speed of the tip of the second
hand of the same length?
Answer in units of m/s.

(b)What is the centripetal acceleration of the tip
of the second hand?
Answer in units of m/s2

60 times as fast

2 pi r in 60 seconds is the speed which we got in part a
so we can solve for r
then
Ac = v^2/r

To find the speed of the tip of the second hand, we can use the relationship between the lengths of the minute hand and the second hand. Assuming both hands have the same length, the second hand will also have a speed of 0.00136 m/s.

(a) Speed of the tip of the second hand = 0.00136 m/s

To calculate the centripetal acceleration of the tip of the second hand, we can use the formula for centripetal acceleration:

Centripetal acceleration = (angular speed) squared multiplied by (radius)

The angular speed of the second hand is given by the formula:
Angular speed = (2 * pi) divided by (time for one complete revolution)

Since the second hand takes 60 seconds to complete one revolution, we can substitute the values into the formulas to find the centripetal acceleration.

(b) Centripetal acceleration of the tip of the second hand = (angular speed)^2 * (radius)

The radius of the clock hand is given as the length of the second hand.