posted by tatychass on .
a plane is flying southwest at 155 mi/h and encounters a wind from the west at 45.0 mi/h. what is the plane velocity in respect to the ground in standard position?
The west component of velocity is reduced becasue of the west wind to 155cos45 - 45 = 64.6 mph (relative to the ground).
The south component of speed remains 155 sin45 = 109.6 mph
The new ground speed is the hypotenuse:
sqrt[(109.6)^2 + (64.6)^2] = 127.2 mph