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September 2, 2014

September 2, 2014

Posted by **ASD** on Friday, September 17, 2010 at 10:02am.

a.Solve the equation w=Cr^-2 for r. The answer I came up with is r^-2=w/C: is this correct?

And would you please help me with b?

b.Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the Earth.)

Thank you!

- Math -
**ASD**, Friday, September 17, 2010 at 11:03amOk, I went back and tried again. The equation I found when solving for r is r=sqrt(C/w)

Is this correct?

Then in b I would plug in the 100 for w, and the 3,963 for r to find the constant, C, correct?

- Math -
**PsyDAG**, Friday, September 17, 2010 at 11:06ama is correct.

C = w/r^-2

w = 100

r = 1/(3963)^2

Solve for C.

- Math -
**ASD**, Friday, September 17, 2010 at 11:29amSo would my equation be C=100/(3963)^2 ...I'm confused

- Math -
**ASD**, Friday, September 17, 2010 at 11:57amPlease let me know if I did this correct for b...

100=C/(3,963)^2

100=C/15,705,369

100*C=(C/15,705,369)*C

100C=15,705,369

100C/100=15,705,369/100

C=157,053.69

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