Posted by vonne on Thursday, September 16, 2010 at 10:11pm.
A hot air balloon is descending at a rate of 2.4 m/s when a passenger drops a camera.
(a) If the camera is 50 m above the ground when it is dropped, how long does it take for the camera to reach the ground? (s)
(b) What is its velocity just before it lands? Let upward be the positive direction for this problem. (m/s)

physics  bobpursley, Thursday, September 16, 2010 at 10:13pm
a) The initial velocity is 2.4m/s
hf=ho+Vi*t4.9t^2
hf=0, hi=50, Vi given, solve for t.
b) Vf=Vi9.8t

physics  Heather, Thursday, September 16, 2010 at 10:18pm
ok so the rate that the camera is dropped is the same as the balloon is the camera's initial velocity. the change in x is 50m and the acceleration is
9.8m/s^2 due to gravity.
a) use the equation, change in x= Vot + 1/2at^2 to find the time for the camera to reach the ground
so you now have the time, initial velocity, and acceleration
b) use the equation V= Vo + at to find the final velocity just before it lands

physics  ju, Friday, September 24, 2010 at 4:12pm
A hotair balloon is descending at a rate of 1.5 when a passenger drops a camera.If the camera is 41 above the ground when it is dropped, how long does it take for the camera to reach the ground?
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