In the movie"Speed" the bus jumps a bridge.Given that the bus is traveling at 31 meters/sec,and the distanceis 15 meters, and the timeis.48 seconds,what is the minium angle required for the bus to reach the distance?

To find the minimum angle required for the bus to reach the distance, we can use trigonometry. Specifically, we will use the trigonometric function of sine.

The given information is:
- Bus speed (v) = 31 meters/sec
- Distance traveled (d) = 15 meters
- Time taken (t) = 0.48 seconds

First, let's find the vertical displacement of the bus when it travels the given distance. We know that the vertical displacement (h) can be calculated using the equation h = v * t.

h = 31 m/s * 0.48 s
h = 14.88 meters

Now, we have the vertical displacement (h) and the horizontal displacement (d). To find the angle (θ), we can use the equation theta = arcsin(h / d).

θ = arcsin(14.88 m / 15 m)

Using a calculator, we can find the arcsine of (14.88 / 15):

θ ≈ 89.97 degrees

Therefore, the minimum angle required for the bus to reach the given distance is approximately 89.97 degrees.