posted by trace .
assume the half-life of the substance is 31 days and the initial
amount is 183.9 grams.
(a) Fill in the right hand side of the following equation which expresses
the amount A of the substance as a function of time t (the coefficient of t in the exponent should have at least four significant digits):
(b) When will the substance be reduced to 2.4 grams?
There is not "followiong equation" to fill in.
Amount left = 183.9*2^(-t/31)
You don't need 4 sig figs in the exponent in this form if the half life is exactly 31 days.
(b) When amount left = 2.4,
2.4/183.9 = 0.01088 = 2^(-t/31)
-4.5212 = (-t/31)*ln 2 = -0.02236t
t = 202.2 days
the second answer is 194.052 days