A square is folded in half to form a rectangle. If the resulting rectangle has a perimeter of 15 inches,what is the are of the original square?HELP...please?

CeCe -- please do not post answers when you don't know! You're just confusing other students.

15=2(s+(s/2))

15=2s+s
15=3s
s=5in

A=s^2

With a little trial and error, I figured that the dimensions of the rectangle are 2.5 by 5

That means that the original square has 5 inches on each side.

Take it from there.

To find the area of the original square, we need to determine the length of the sides of the square. Let's break down the problem step by step.

1. Let's assume that the original square has side length 'x' inches. So, each side of the square is 'x' inches long.

2. When the square is folded in half, it forms a rectangle. The length of the rectangle will be the same as the side length of the square, 'x' inches. The width of the rectangle can be calculated by dividing the side length of the square by 2, as it is folded in half. Thus, the width of the rectangle is 'x/2' inches.

3. The perimeter of a rectangle is calculated by adding up the lengths of all its sides. In this case, the perimeter of the rectangle is given as 15 inches. Since the length and width of the rectangle are 'x' inches and 'x/2' inches, respectively, we can write the equation: 2(x + x/2) = 15.

4. Simplifying the equation, we have 2(3x/2) = 15. Solving for 'x', we get 3x = 15, which gives us x = 5.

5. Now that we know the side length of the square is 5 inches, we can calculate its area by multiplying the length of one side by itself: 5 * 5 = 25 square inches.

Therefore, the area of the original square is 25 square inches.

15x4=60 or 15x5=75.

I'm not sure?