Posted by Joey on Thursday, September 16, 2010 at 4:35pm.
h=1/2 g t^2 is the basic formula.
H=1/2 g (t-to)^2 where to is the time the lower one is dropped, after the higher.
4H=1/2 g t^2
So, both balls hit at time t.
t=sqrt 8H/g
H=1/2 g (sqrt(8H/g)-to)^2
2H=g(8H/g-2to*sqrt(8H/g)+to^2)
so you have a quadratic...
to^2-2to* sqrt(8H/g)-2H/g
a=1 b=-2sqrt(8H/g) c= -2H/g
solve by the quadratic equation.
Related Questions
Physics - Two balls are dropped from rest from the same height. One of the balls...
physics - two balls are dropped to the ground from different heights. one ball ...
physics - How many secons apart should two balls be released so that a ball ...
physics - A mass is dropped from a height of 30m, and at the same time from ...
physics - A mass is dropped from a height of 30m, and at the same time from ...
physics - A foam cube bounces to a height of 15cm when dropped from a height of ...
Physics - A mass is dropped from a height of 30m, and at the same time from ...
math - the height that a ball bounces varies directly as the height from which ...
Physics - Near the surface of the Earth there is an electric field of about V=...
Physics - Near the surface of the Earth there is an electric field of about V=...
For Further Reading
