A uniform electric field of magnitude 370 N/C pointing in the positive x-direction acts on an electron, which is initially at rest. The electron has moved 2.70 cm.

(a) What is the work done by the field on the electron?
J?

(b) What is the change in potential energy associated with the electron?
J?

(c) What is the velocity of the electron?
magnitude? m/s
direction



2.
Oppositely charged parallel plates are separated by 5.26 mm. A potential difference of 600 V exists between the plates.
(a) What is the magnitude of the electric field between the plates?
N/C?

(b) What is the magnitude of the force on an electron between the plates?
N?

(c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.94 mm from the positive plate?
J?

1 A) W = e*E*X

X must be in meters to get the Work in Joules. e is the elctron chrge
B) -W
C) (1/2) m v^2 = W
Solve for velocity v

2. (a) E = V/d
d must be in meters
(b) e*E
(c) It is 2.32 cm = 0.0232 m from the positive plate. Call that distance X'

Work = e E x'

How do you determine the electric charge? What does X represent?

Actually I know them now but what is M for C) on the third question?

for the first question i mean

M is the mass of the electron.

9.108*10^-31 kg

To find the answers to these questions, we'll use relevant formulas and equations from the field of electrostatics. Let's break down each question and go step by step to find the answers.

1. For the first question:
(a) The work done on an electron moving in an electric field is given by the equation:
Work = Force × Distance
In this case, the force on the electron is given by the product of the electric field and the charge of the electron. The distance moved by the electron is given as 2.70 cm, but we need to convert it to meters. The charge of an electron is -1.6 × 10^-19 C.
Therefore, the work done is:
Work = (Force × Distance) = (Electric Field × Charge) × Distance

Let's substitute the given values:
Electric Field = 370 N/C
Charge of an electron = -1.6 × 10^-19 C
Distance = 2.70 cm = 2.70 × 10^-2 m

Plugging in the values into the equation:
Work = (370 N/C × -1.6 × 10^-19 C) × 2.70 × 10^-2 m

Calculate the value to find the work done in joules (J).

(b) The change in potential energy is equal to the work done by the electric field:
Change in Potential Energy = Work done
We already calculated the work done in part (a), so the change in potential energy has the same value.

(c) To find the velocity of the electron, we can use the work-energy theorem, which states:
Work done on an object = Change in kinetic energy
The work done on the electron by the electric field is equal to the change in its kinetic energy. Kinetic energy is given by the equation: Kinetic Energy = (1/2) × mass × velocity^2
Since the electron is initially at rest, its initial kinetic energy is zero. Therefore, the work done by the field is equal to its final kinetic energy.

Let's equate the work done by the field to the final kinetic energy:
Work done = Change in kinetic energy
From part (a), we already calculated the work done. We can equate it to the kinetic energy:
Work = (1/2) × mass × velocity^2

Rearranging the equation to solve for velocity:
velocity^2 = (2 × Work) / mass
Taking the square root of both sides will give us the velocity.

Now, let's move on to the second set of questions.

2. For the second question:
(a) The magnitude of the electric field between the plates is given by the equation:
Electric Field = Potential Difference / Distance
The potential difference is given as 600 V, and the distance between the plates is 5.26 mm. We need to convert it to meters.

Plugging in the values into the equation:
Electric Field = 600 V / 5.26 × 10^-3 m

Calculate the value to find the magnitude of the electric field in N/C.

(b) The force on the electron between the plates can be calculated using the equation:
Force = Electric Field × Charge
The electric field is already calculated in part (a), and the charge of an electron is -1.6 × 10^-19 C.

Plugging in the values into the equation:
Force = Electric Field × Charge

Calculate the value to find the magnitude of the force in Newtons (N).

(c) To find the work done on the electron to move it to the negative plate, we can use the equation:
Work = Charge × Potential Difference
The charge of an electron is -1.6 × 10^-19 C, and the potential difference is given as 600 V. The initial distance from the positive plate to the electron is given as 2.94 mm, which needs to be converted to meters.

Plugging in the values into the equation:
Work = Charge × Potential Difference

Calculate the value to find the work done in joules (J).

By following these steps and calculations, you can find the answers to all the questions posed.