Posted by **Phil** on Thursday, September 16, 2010 at 12:32am.

{ The subscripts are in curly brackets }

A mass m is at rest on a horizontal frictionless surface at t=0. Then a constant force F{0} acts on it for a time t{0}. Suddenly, the force doubles to 2F{0} and remains constant until t=2t{0}. Determine the total distance D traveled from t=0 to t=2t{0}. Express your answer in terms of F{0}, t{0}, and m.

- Physics -
**drwls**, Thursday, September 16, 2010 at 7:51am
Get the acceleration from F = ma

During the first period,

a = F{0}/m and the displacement is

(1/2)*(F{0}/m)*t{0}^2

During the second period it travels twice as far, since the period of acceleration at the higher (doubled) rate is the same.

Add the two displacements

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