Posted by Jennifer on Wednesday, September 15, 2010 at 10:26pm.
A ball is thrown vertically upward with a
speed of 25.4 m/s from a height of 2.1 m. (Remember gravity is a=9.8m/s^2)
How long does the ball take to hit the ground after it reaches its highest point?
Answer in units of s.

Physics  Angela, Wednesday, September 15, 2010 at 10:38pm
make a parobala, find the highest point find the time for the whole thing, then dive the time in half. hope that kind of helped !

Physics  drwls, Wednesday, September 15, 2010 at 10:43pm
height Y = 2.1 + 25.5 t  4.9 t^2
Solve for the time Y = 0
It reaches its highest point when t = Vo/g = 25.4/9.8 = 2.59 s
Since they want the time it takes to hit the ground AFTER reaching the highest point, you will need to subtract 2.59s from the time Y=0
There is another way to do this without solvoing a quadratic equation>
1) use conservation of energy to calculate how much higher high it goes.
g*(deltaY) = Vo^2/2
2) Add the initial elevation, 2.1 m, to delta Y. That will give you Ymax
3) T (time to fall from max height)
= sqrt (2 Ymax/g)

Physics  Anonymous, Monday, October 17, 2016 at 7:18pm
1,\m/s
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