molal (again)
posted by lisa .
i tried to solve it on my own but im confused about the last part, this i what i have so far..
moles of glycerin= 50.0/92.10=0.54
molality=0.54/0.200=2.7
is that right?
im a little confused about the numbers im supposed to use for step 3...
this was the question:
the freezing point of ethanol (C2H5OH) is 114.6C. the molal freezing point depression constant for ethanol is 2.00C/m. what is the freezing point (C) of a solution prepared by dissolving 50.0 g of glycerin (C3H8O3, A nonelectrolyte) in 200 g of ethanol.

yes,
molal= molessolute/kgsolvent
You have it correct. 
im not sure about the last step tho... i know the final answer is 120.0 but im not sure how to get to that...