Homework Help: molal (again)

Posted by lisa on Wednesday, September 15, 2010 at 7:55pm.

i tried to solve it on my own but im confused about the last part, this i what i have so far..

moles of glycerin= 50.0/92.10=0.54
molality=0.54/0.200=2.7
is that right?

im a little confused about the numbers im supposed to use for step 3...

this was the question:

the freezing point of ethanol (C2H5OH) is -114.6C. the molal freezing point depression constant for ethanol is 2.00C/m. what is the freezing point (C) of a solution prepared by dissolving 50.0 g of glycerin (C3H8O3, A nonelectrolyte) in 200 g of ethanol.

molal (again) - bobpursley, Wednesday, September 15, 2010 at 8:00pm
yes,

molal= molessolute/kgsolvent
You have it correct.
molal (again) - lisa, Wednesday, September 15, 2010 at 8:13pm
im not sure about the last step tho... i know the final answer is -120.0 but im not sure how to get to that...

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