Posted by Jennifer on Wednesday, September 15, 2010 at 8:08am.
During the engineer's reaction time, the train travels 26 x 0.62 = 16 meters. To avoid a collision after that, the train's speed must be reduced to zero while traveling less than 194 m.
While decelerating, the average speed will be 26/2 = 13 m/s
Maximum stopping time
= (194 m)/(13 m/s) = 14.92 s
Required deceleration rate
= (26 m/s)/14.92s = ____ m/s^2
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