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algebra

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the perimeter of a rectangle is 222 inches. the length exceeds the width by 47 inches. what is the length and width

  • algebra - ,

    width -- x
    length -- x+47

    solve
    2(x + x+47) = 222

  • algebra - ,

    P=2l +2w
    222 = 2(w+47) + 2w
    222= 2w +94 +2w
    222=4w+94
    222-94=4w+94-94
    128=4w
    32=w so length = w+47
    length = 32+47=79

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