Posted by Angel on Tuesday, September 14, 2010 at 10:48pm.
B = base
A = acid = BH^+
B.Na + H^+ ==> A (BH^+)
pH = pKa + log[(base)/(acid)]
Plug in 8.00 for pH, 7.55 for pKa, and solve for ratio B/A.
You need another equation since there are two unknowns; and that one is A + B = 0.1M
Solve for A and B.
Then I would start with 0.1 mole B.Na which is 0.1 x 260.3 = ?? grams (I think about 26 grams). You know the concn needed for the acid and that MUST equal the H^+ needed. That will give you L of the 6M HCl needed and that should do it. Post your work if you get stuck. I arrived at about 26 grams of the sodium salt and about 4.5 mL of the acid (actually a little less), then make the solution to a final volume of 1.00 L in a volumetric flask.
I am a little confused on the part after you solve for 26 grams. Can you explain a little more? Thanks
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