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Posted by Deanna on Tuesday, September 14, 2010 at 10:45pm.

y=4x^2-16x+12

4(x^2-4x+3) You can factor this further by seeing which 2 numbers subtract to 4 (your middle term) and add to 3 (your last term). Post if you want it checked/need help.

4[x^2-3x-x+3] =4[x[x-3)-1(x-3)] =4[x-1][x-3]

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