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September 20, 2014

September 20, 2014

Posted by **Preston** on Tuesday, September 14, 2010 at 9:25pm.

lines:

(a) having slope ¡1 and passing through (0; 2)

(b) parallel to y=2x-1 and passing through (¡2; 0)

(c) passing through (1; 0) and (¡1; 3)

(d) with x-intercept 6 and y-intercept 3.

- Calculus -
**Preston**, Tuesday, September 14, 2010 at 9:59pmI have no clue where to begin.

- Calculus -
**TutorCat**, Tuesday, September 14, 2010 at 10:13pmy-y1=m(x-x1)+b

where m=slope and b=y-intercept

(a)m=1, x1=0, y1=2

(b)since it's parallel, we know that the slopes are equal; m=2

(c)m=(y1-y2)/(x1-x2)

y-y1=m(x-x1)+b

(d)since x-intercept is equal to 6, we know (6, 0). since y-intercept is equal to 3, we know (0,3).

Find the slope: m=(y1-y2)/(x1-x2)

Plug into slope and one of the two coordinates: y-y1=m(x-x1)+b

- Calculus -
**Preston**, Tuesday, September 14, 2010 at 10:22pmThanks so much helps a lot.

- Calculus -
**MathMate**, Tuesday, September 14, 2010 at 10:47pmPreston, check if the slope shouldn't be

"-1" in

"(a) having slope ¡1 and passing through (0; 2) "

Your computer seems to have a problem getting the negative sign.

- Calculus -
**Preston**, Tuesday, September 14, 2010 at 11:00pmyea it is having trouble. thanks again. i am just stuck on my other one now

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