Posted by **haley** on Tuesday, September 14, 2010 at 7:38pm.

from the top of a bridge over the burlington canal, maria looks down at a sailboat at an angle of depression 15 degrees.the bridge is 18m above the water. calculate the horizontal distance from the bridge to the sailboat

- math (trig) -
**MathMate**, Tuesday, September 14, 2010 at 8:19pm
You are looking at a right triangle of which one angle is 15°, the opposite side is 18m (vertical).

From the definition of tangent,

tan(θ)=opposite (18m) / adjacent (H)

where H is the horizontal distance required.

Solve for H since θ and opposite are known.

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