how many moles of solute is present in 40.0mL of 1.000 M of HNO3
Well, I don't know about you, but I think moles are quite stealthy creatures. They don't usually make appearance in solvents like HNO3. But to answer your question, we can calculate the number of moles using the formula:
moles = concentration × volume
So in this case, we have a concentration of 1.000 M and a volume of 40.0 mL. Let's go ahead and do the calculation for some mole-ificent fun:
moles = 1.000 M × 0.0400 L
And the answer is... ta-da!
moles = 0.040 moles of HNO3
So, there are approximately 0.040 moles of HNO3 in 40.0 mL of 1.000 M HNO3.
To calculate the number of moles of solute (HNO3) present in a solution, you need to use the formula:
moles = concentration (M) x volume (L)
Given:
Concentration (M) = 1.000 M
Volume (mL) = 40.0 mL
Firstly, convert the volume from milliliters (mL) to liters (L):
40.0 mL = 40.0/1000 = 0.040 L
Now, substitute the values into the formula:
moles = 1.000 M x 0.040 L = 0.040 moles
Therefore, there are 0.040 moles of solute (HNO3) present in 40.0 mL of 1.000 M HNO3.
To determine the number of moles of solute in a solution, we need to use the formula:
moles = concentration (M) x volume (L)
Given:
Concentration (M) = 1.000 M
Volume (mL) = 40.0 mL
To use the formula, we have to convert the volume from mL to L because the concentration is given in moles per liter (M).
1 L = 1000 mL
So, we convert the volume from mL to L:
40.0 mL ÷ 1000 mL/L = 0.0400 L
Now we can substitute the values into the formula:
moles = concentration (M) x volume (L)
moles = 1.000 M x 0.0400 L
Now we can calculate the number of moles:
moles = 0.0400 mol
Therefore, there are 0.0400 moles of HNO3 in 40.0 mL of a 1.000 M solution.
remember to convert 40.0 mL into liters
(40.0 mL)(1L/1000mL) = ?
Molarity (M) = moles of solute/ volume of solution in liters