Posted by calc on Tuesday, September 14, 2010 at 2:41pm.
Find an equation of the tangent line to the curve at the given point.
y = 6 x sin x
P= (pi/2 , 3pi)
i know the slope of a tangent line is equal to the first derivative. For that I got 6xcosx + 6sinx but idk how to put that into the yy1=m(xx1) formula to make the equation

calc  TutorCat, Tuesday, September 14, 2010 at 2:44pm
great job on the first derivative!
m=slope
m= 6(pi/2)cos(pi/2) + 6sin(pi/2)
y1=3pi
x1=pi/2

calc  calc, Tuesday, September 14, 2010 at 2:48pm
oh! ok! thank you!
so then m=6 and the equation of the tangent line would be y=6x
Thank you!

calc  TutorCat, Tuesday, September 14, 2010 at 2:56pm
remember to plug in your y1 and x1 & solve for y!
yy1=m(xx1)
y3pi=6(xpi/2)
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