Posted by **calc** on Tuesday, September 14, 2010 at 2:41pm.

Find an equation of the tangent line to the curve at the given point.

y = 6 x sin x

P= (pi/2 , 3pi)

i know the slope of a tangent line is equal to the first derivative. For that I got 6xcosx + 6sinx but idk how to put that into the y-y1=m(x-x1) formula to make the equation

- calc -
**TutorCat**, Tuesday, September 14, 2010 at 2:44pm
great job on the first derivative!

m=slope

m= 6(pi/2)cos(pi/2) + 6sin(pi/2)

y1=3pi

x1=pi/2

- calc -
**calc**, Tuesday, September 14, 2010 at 2:48pm
oh! ok! thank you!

so then m=6 and the equation of the tangent line would be y=6x

Thank you!

- calc -
**TutorCat**, Tuesday, September 14, 2010 at 2:56pm
remember to plug in your y1 and x1 & solve for y!

y-y1=m(x-x1)

y-3pi=6(x-pi/2)

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