Posted by **carly** on Tuesday, September 14, 2010 at 3:29am.

Assume that the student

has a cup with 15 writing implements: 8 pencils, 5 ball

point pens, and 2 felt-tip pens.In how many ways can the selection be made if no more than one ball

point pen is selected?

- finite math -
**Reiny**, Tuesday, September 14, 2010 at 7:53am
"In how many ways can **the selection** be made if no more than one ball point pen is selected?"

your question is not clear.

Are the pencils all the same ? etc

Is one ball-point, 6 pencils and 2 felt-tips a "selection" ?

Is just one pencil a "selection" ?

You have to define what you mean by a selection.

- finite math -
**Reiny**, Tuesday, September 14, 2010 at 8:24am
I thought it over and I would do it this way:

the pencils can be taken in 9 ways, that is,

take none, 1,2,3,.. or 8 of them

the ball-point pens can be taken in 2 ways, none or 1

the felt-tips in 3 ways, none, one or both.

number of selections = 9(2)(3) or 54

But that would include the case of taking none at all, which would not be a selection,

so number of selections is 54-1 or

53 ways.

- finite math -
**NATHAN**, Thursday, September 16, 2010 at 12:20am
I don't know the answer but i know the answer is not 53. Not all info was givin to complete the problem. It should have read that they student will select 5 writing implements. How many ways if only one ball poin at selected.

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