Posted by **David D.** on Tuesday, September 14, 2010 at 2:06am.

A long, thin straight wire with linear charge density -λ runs down the center of a thin, hollow metal cylinder of radius R. The cylinder has a net linear charge density 2λ. Assume λ is positive. Find expressions for the electric field at the following locations. Use lambda for λ, pi for π, epsilon_0 for ε0, r for r, and R for R.

(b) outside the cylinder, r > R

- physics -
**drwls**, Tuesday, September 14, 2010 at 2:15am
Use Gauss' law. Because of symmetry, the E field will be radially outward and a function of r only.

The product of E and the area of any imaginary concentric cylinder (Gauss' law surface) outside r = R is equal to the charge inside the cylinder, divided by epsilono. E will be inversely proportional to r.

Review or use Google look up Gauss' law if you are unfamiliar with it. Here is one good reference among many:

http://teacher.pas.rochester.edu/phy122/Lecture_Notes/Chapter24/Chapter24.html

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