Posted by Asher on Tuesday, September 14, 2010 at 12:18am.
It will be a parabola. The vertical axis will be at x = -3. F is the focal point. The vertex of the parabola is equidistant from F and the y = -2 line, at x = -3, y = 1.
y = a (x+3)^2 + 1 is the equation.
Do some reading up on parabolas to figure out what a is. I think you will find it is 4 times the distance from the focus to the vertex, or 4*3 = 12
That would make the equation
y = 12(x+3)^2 + 1
Expand and rearrange that to the "general form".
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