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July 24, 2014

July 24, 2014

Posted by **sarabeth** on Monday, September 13, 2010 at 11:45pm.

Need to solve the equation algebraically

- cubic equation solving -
**drwls**, Tuesday, September 14, 2010 at 12:08amIF there is a rational real root, it is q/p, where p and q are integer factors of the x^3 term and the constant term. Once you have one root (by trial and error), the others can be obtained by solving the quadratic you get by factoring out the first root.

In your case, one of the roots is 2. Divide the cubic by x-2 to get the quadratic that will get you the other two roots.

If you are lazy like me and want to peek at the answers, use:

http://www.cubicsolver.com/

- 11th grade -
**jordan**, Tuesday, September 14, 2010 at 6:35pmAngle QRS is a straight angle. If a=2c, c=2b, and b=d/3, what are the values of a,b,c,and d? a+b+c+d = 180

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