posted by sarabeth on .
4 x^3 - 4x^2 - 11x + 6 = 0
Need to solve the equation algebraically
IF there is a rational real root, it is q/p, where p and q are integer factors of the x^3 term and the constant term. Once you have one root (by trial and error), the others can be obtained by solving the quadratic you get by factoring out the first root.
In your case, one of the roots is 2. Divide the cubic by x-2 to get the quadratic that will get you the other two roots.
If you are lazy like me and want to peek at the answers, use:
Angle QRS is a straight angle. If a=2c, c=2b, and b=d/3, what are the values of a,b,c,and d? a+b+c+d = 180